以下将在 SQL SELECT 语句中使用 ORDER BY 子句来读取MySQL 数据表 tutorials_tbl 中的数据:
尝试以下实例,结果将按升序排列
root@host# mysql -u root -p password; Enter password:******* mysql> use TUTORIALS; Database changed mysql> SELECT * from tutorials_tbl ORDER BY tutorial_author ASC +-------------+----------------+-----------------+-----------------+ | tutorial_id | tutorial_title | tutorial_author | submission_date | +-------------+----------------+-----------------+-----------------+ | 2 | Learn MySQL | Abdul S | 2007-05-24 | | 1 | Learn PHP | John Poul | 2007-05-24 | | 3 | JAVA Tutorial | Sanjay | 2007-05-06 | +-------------+----------------+-----------------+-----------------+ 3 rows in set (0.42 sec) mysql>
读取 tutorials_tbl 表中所有数据并按 tutorial_author 字段的升序排列。
尝试以下实例,查询后的数据按 tutorial_author 字段的降序排列后返回。
<?php
$dbhost = 'localhost:3036';
$dbuser = 'root';
$dbpass = 'rootpassword';
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(! $conn )
{
die('Could not connect: ' . mysql_error());
}
$sql = 'SELECT tutorial_id, tutorial_title,
tutorial_author, submission_date
FROM tutorials_tbl
ORDER BY tutorial_author DESC';
mysql_select_db('TUTORIALS');
$retval = mysql_query( $sql, $conn );
if(! $retval )
{
die('Could not get data: ' . mysql_error());
}
while($row = mysql_fetch_array($retval, MYSQL_ASSOC))
{
echo "Tutorial ID :{$row['tutorial_id']} <br> ".
"Title: {$row['tutorial_title']} <br> ".
"Author: {$row['tutorial_author']} <br> ".
"Submission Date : {$row['submission_date']} <br> ".
"--------------------------------<br>";
}
echo "Fetched data successfully\n";
mysql_close($conn);
?>